Leap Year Program in Python

In this article of Leap Year Program in Python, we will see whether a entered year is a leap year or not. For checking a year we have knowledge of followings :-

1. Operators.
2. If-Else Statement.

A leap year is exactly divisible by 4 except for century years (years ending with 00) Like 400,800 etc.

Leap Year Program in Python

# To get year (integer input) from the user
year = int(input("Enter a year: "))

# divided by 100 means century year (ending with 00)
# century year divided by 400 is leap year
if (year % 400 == 0) and (year % 100 == 0):
    print(+year," is a leap year")

# not divided by 100 means not a century year
# year divided by 4 is a leap year
elif (year % 4 ==0) and (year % 100 != 0):
    print(+year," is a leap year")

# if not divided by both 400 (century year) and 4 (not century year)
# year is not leap year
else:
    print(+year," is not a leap year")

Output :-

Enter a year : 2020
2020  is a leap year

Hope, after going through the whole article, all your doubts are cleared related leap year in python.

Also Read : Inheritance in Python – OOPS Concepts

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